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26 July, 22:51

How many solutions exist for the given equation?

12x + 1 = 3 (4x + 1) - 2

zero

one

two

infinitely many

+1
Answers (2)
  1. 26 July, 23:41
    0
    Step-by-step explanation:

    12x + 1 = 3 (4x + 1) - 2

    12x + 1 = 12x + 3 - 2

    Zero solution
  2. 27 July, 01:02
    0
    Infinitely many

    Step-by-step explanation:

    12x + 1 = 3 (4x + 1) - 2

    12x + 1 = 12x + 3 - 2

    12x + 1 = 12x + 1

    Both sides are equal for all x, so infinite solutions
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