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25 January, 17:25

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 L of a dye solution with a concentration of 1 g/L. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 L/min, the well-stirred solution flowing out at the same rate.

a. Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

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  1. 25 January, 19:36
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    Answer: t = 460.52 minutes

    Step-by-step explanation:Q'=Q/100

    Q' = rate in and out of water

    Finding the differential equation

    Let Q' (t) = The quantity of dye in the tank for t time

    But rate in=0 Q/200 * 2=Q'

    Q'/Q=-1/100

    Dividing by Q gives

    Ln/Q / + c = - 1/100 + c1

    Integrating both sides gives

    Ln/Q / = - (1/100) t + c2

    But c+c1=C2 = A constant

    Q=C2e (-t/100)

    200e - (t/100)

    t = ln200

    t=460.52minutes
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