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23 May, 03:10

If the angles are represented in degrees, find both angles: / cos (3x+13) = / sin (2x+42) cos (3x+13) = sin (2x+42)

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  1. 23 May, 05:01
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    cos34°

    sin56°

    Step-by-step explanation:

    Sin (2x+42) = sin90 - (3x+13)

    Sin (2x+42) = sin (90-13-3x)

    Sin (2x+42) = sin (77-3x)

    2x + 42 = 77-3x

    5x. = 35

    X = 7

    If x = 7

    cos (3x+13) = cos ((3*7) + 13)

    cos (3x+13) = cos (21+13)

    cos (3x+13) = cos34

    And

    sin (2x+42) = sin ((2*7) + 42)

    sin (2x+42) = sin (14+42)

    sin (2x+42) = sin56
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