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30 May, 05:42

A jet climbs at a steady rate at an angle of inclination of 0.5 degree during take-off. What will its he height be after a 2.2 km initial ascent at this angle at this angle?

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  1. 30 May, 08:33
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    Answer: Height = 0.019km

    Step-by-step explanation:

    Things to consider;

    The distance of the jet at the angle 0.5°

    The vertical distance of the jet from the ground

    The horizontal distance of the jet

    Using imaginary lines these three components will form a right angle triangle which provides us valuable information in calculating the height of the jet from the ground.

    Using the formulae: Sine of an angle = opposite side / hypotenuse side

    Where the opposite side is the side opposite to the angle 0.5 which is the height of the jet.

    The hypotenuse side is the distance of the jet at the angle 0.5

    Therefore, Sine 0.5 = height / 2.2km

    Height = Sine 0.5*2.2

    Height = 0.0087*2.2 = 0.019km

    Hence the height is 0.019km
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