Given the equation square root of 2x-1=7 solve for x and identify if it is an extraneous solution. I came up with the answer 25 but is it an extraneous solution?

Step-by-step explanation:

To check if a solution is extraneous, simply plug it back into the original equation. If it works, then solution isn't extraneous.

√ (2x-1) = 7

√ (2 (25) - 1) = 7

√ (50-1) = 7

√ (49) = 7

7 = 7

So the solution isn't extraneous.