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8 August, 18:37

A mass of 7kg is held in equilibrium by 2

ropes. One has tension 20N and acts on 90 degrees

to the vectical. Find the tension in other

ropes and the angle itself make with vectical.

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Answers (1)
  1. 8 August, 22:34
    0
    71.52 N and 16.24 degrees.

    Step-by-step explanation:

    Let the tension in the second rope be T N and the angle with the vertical be x degrees.

    Resolving forces;

    Vertically: 7g = T cos x

    Horizontally: 20 = T sin x

    T sin x / T cos x = tan x

    So tan x = 20 / 7g

    = 20 / (7 * 9.81

    = 0.29124

    So x = arctan 0.29124

    = 16.24 degrees.

    The tension T = 7g / cos 16.24

    = 71.52 N.
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