Choose an American adult at random. The probability that you choose a woman is 0.52. 0.52. The probability that the person you choose has never married is 0.26. 0.26. The probability that you choose a woman who has never married is 0.11. The probability that the person you choose is either a woman or has never been married (or both) is therefore а bout:

(a) 0.77.

(b) 0.66.

(c) 0.44.

(d) 0.38.

(e) 0.13.

The probability that the person you choose is either a woman or has never been married (or both) is therefore about 0.66

Step-by-step explanation:

Given dа ta:

Probability of choosing a women = P (W) = 0.52

Probability that chosen person has never married = P (M) = 0.26

Probability of choosing a women that has never married = P (W and M) = 0.11

We need to find the probability that the person you choose is either a woman or has never been married (or both). The addition rule of probabilities of two events is given as:

P (A or B) = P (A) + P (B) - P (A and B)

P (A or B) is the probability of occurrence of either A or B or both. P (A and B) is the probability of occurrence of A and B at the same time.

Re-writing the addition formula for given case, we get:

P (W or M) = P (W) + P (M) - P (W and M)

Substituting the given values results in:

P (W or M) = 0.52 + 0.26 - 0.11

P (W or M) = 0.67

Therefore, the probability that the person you choose is either a woman or has never been married (or both) is 0.67.

Note: There is either typo in given options or the questions. The question I found on Google has 0.25 as the probability that the person you choose has never married (i. e. P (M) = 0.25).

So, in this case the correct answer would be option (b) 0.66