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6 June, 08:04

Assume the average weight of an American adult male is 180 pounds with a standard deviation of 34 pounds. The distribution of weights follows a normal distribution. What is the probability that a man weighs somewhere between 120 and 155 pounds?

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  1. 6 June, 10:10
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    Step-by-step explanation:

    Find a-score of both

    z-score = (x-mean) / SD

    for 120

    z = (120 - 180) / 34 = - 1.765

    For 155

    z = (155-180) / 34 = - 0.735

    The probability to look for using z-score table is;

    P (-1.765
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