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17 April, 00:43

Algebra: mrs. Davis spent $120 on lunch for a business meeting. Sandwiches, x, cost $4 and drinks, y, cost $1.50. A) write a function that relates the number of sandwiches and drinks purchased for lunch b) find three pairs of solutions to your equations above

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  1. 17 April, 01:24
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    a) Total number of Sandwiches and drinks purchased = x + y

    b) The three possible solution to the given equation is

    : (25,4), (20,8) and (15,12)

    Step-by-step explanation:

    Number of sandwiches in Lunch = x

    Cost of each sandwich = $4

    Number of Drinks in Lunch = y

    Cost of each drink = $1.50

    a) So, the total number of Sandwiches and drinks purchased in Lunch

    = Number of sandwiches purchased + Number of drinks purchased

    = x + y

    or, the total number of Sandwiches and drinks purchased = x + y

    Now According to the question:

    4 x + 5 y = 120

    To find possible pairs of solution take any arbitrary value for y.

    Let y = 4, then 4x = 120 - 20 = 100

    or, x = 100/4 = 25 ⇒ x = 25

    Let y = 8, then 4x = 120 - 420 = 80

    or, x = 80/4 = 20 ⇒ x = 20

    Similarly, for y = 12, x = 15

    So, the three possible solution to the given equation is : (25,4), (20,8) and (15,12)
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