Two parallel lines are crossed by a transversal.

Horizontal and parallel lines b and c are cut by transversal a. At the intersection of lines b and a, the bottom left angle is (5 x + 5) degrees. At the intersection of lines c and a, the bottom right angle is 115 degrees.

What is the value of x?

Question

Mathematics

Viviana Carr

8 February, 17:17

Two parallel lines are crossed by a transversal.

Horizontal and parallel lines b and c are cut by transversal a. At the intersection of lines b and a, the bottom left angle is (5 x + 5) degrees. At the intersection of lines c and a, the bottom right angle is 115 degrees.

What is the value of x?

+2

Answers (1)

Know the Answer?

Perla Mcbride · Answer 1

Step-by-step explanation:

b//c; a is transversal

5x + 5 + 115 = 180 { 5x+5 and 115 are supplementary angles}

5x + 120 = 180

5x = 180 - 120

5x = 60

x = 60/5

x = 12

Two parallel lines are crossed by a transversal.Horizontal and parallel lines b and c are cut by transversal a. At the intersection of lines b and a, the bottom left angle is (5 x + 5) degrees. At the intersection of lines c and a, the bottom right angle is 115 degrees.What is the value of x?

Two parallel lines are crossed by a transversal.

Horizontal and parallel lines b and c are cut by transversal a. At the intersection of lines b and a, the bottom left angle is (5 x + 5) degrees. At the intersection of lines c and a, the bottom right angle is 115 degrees.

What is the value of x?