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13 July, 11:05

4[z + 3 (Z - 1) ] = 36

How do you solve this problem?

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Answers (2)
  1. 13 July, 12:22
    0
    3

    Step-by-step explanation:

    4[z+3 (z-1) ]=36

    z+3 (z-1) = 36/4

    z+3z-3=9

    4z-3=9

    4z=9+3

    4z=12

    z=12/4

    z=3
  2. 13 July, 14:46
    0
    4z+2 (square) 2z=2 (square) 6

    Step-by-step explanation:

    4 ((z+3 (z-1))) = 36

    4 (z^2-z+3 ((z-3))) = 36

    4 (z^2-z+3z-3) = 36

    4 ((z^2 + (-z+3z) - 3)) = 36

    4 (z^2+2z-3) = 36

    4z^2+8z-12=36

    4z^2+8z=24

    ((4 (square) z^2)) + (square) 8z = (square) 24

    4z+2 (square) 2z=2 (square) 6
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