A pit was dug in the shape of a cuboid with a dimension 10m*8m*3m. The earth taken out is spread evenly on a rectangular plot of land with dimension 40m * 30m. What is the increase in the level of the plot?

hey buddy here is your answer!

Volume of a cuboid = l * b * h

Volume of earth dug out = 10 * 8 * 3 = 240 m^3

Volume of earh dug = 40 * 30 * height of the rectangular plot

240 = 40 * 30 * h

240 = 1200 * h

240 = 1200h

h = 240 / 1200 = 20 / 100 = 1 / 5 = 0.2

h = 0.2 m

So the plot height increased by 0.2 m or 200cm.

First we find the volume of the pit so 10*8*3 which is 240m^3

then we need the area of the plot which is 40*30=1200m^2

now we need to find out how many times 1200 goes into 240 to see how many meters it's increased by (it will be less than 1)

we can put this as a fraction so 240/1200

1/5

0.2m increase