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28 February, 12:33

Find four consecutive integers if the sum of the second and fourth is 48

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  1. 28 February, 14:34
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    Step-by-step explanation:

    Let the four consecutive integers be

    x, x+1, x+2, x+3

    According to the given statement the sum of 2nd and 4th is 48 so,

    x+1+x+3=48

    2x+4=48

    2x=44

    x=22

    So the four consecutive integers are

    x=22,

    x+1=23,

    x+2=24,

    x+3=25
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