Solve for y.

2y^2+5y+63 = (y+7) ^2

Answer: y = 2 or 7

Step-by-step explanation:Copy and open the bracket

2y² + 5y + 63 = (y + 7) ²

expand the right hand expression (y + 7) ², which now becomes

y² + 14y + 49, now equate the 2 together and arrange it into a quadratic structure

2y² + 5y + 63 = y² + 14y + 49

2y² - y² + 5y - 14y + 63 - 49 = 0

y² - 9y + 14 = 0

Now, factorize the expression using grouping or any method

y² - 7y - 2y + 14 = 0, considering two factors, when multiplied together gives + 14, and when added together gives - 9

Considering the common factors, it now becomes

y (y - 7) - 2 (y - 7) = 0

(y - 2) (y - 7) = 0

To find the root of y,

when y - 7 = 0

y = 7, and when y - 2 = 0, y = 2

Therefore, the solution of the equation is

y = 2, or 7.