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16 July, 16:03

Solve for y.

2y^2+5y+63 = (y+7) ^2

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Answers (1)
  1. 16 July, 16:16
    0
    Answer: y = 2 or 7

    Step-by-step explanation:Copy and open the bracket

    2y² + 5y + 63 = (y + 7) ²

    expand the right hand expression (y + 7) ², which now becomes

    y² + 14y + 49, now equate the 2 together and arrange it into a quadratic structure

    2y² + 5y + 63 = y² + 14y + 49

    2y² - y² + 5y - 14y + 63 - 49 = 0

    y² - 9y + 14 = 0

    Now, factorize the expression using grouping or any method

    y² - 7y - 2y + 14 = 0, considering two factors, when multiplied together gives + 14, and when added together gives - 9

    Considering the common factors, it now becomes

    y (y - 7) - 2 (y - 7) = 0

    (y - 2) (y - 7) = 0

    To find the root of y,

    when y - 7 = 0

    y = 7, and when y - 2 = 0, y = 2

    Therefore, the solution of the equation is

    y = 2, or 7.
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