What are the solutions of the compound inequality 2d + 3 ≤ - 11 or 3d - 9 > 15?

A. d ≤ - 7 or d > 8

B. d ≤ - 4 or d > 2

C. d ≤ - 7 or d > 2

D. d ≤ - 4 or d > 8

A. d ≤ - 7 or d > 8.

Step-by-step explanation:

Given : 2d + 3 ≤ - 11 or 3d - 9 > 15.

To find : What are the solutions of the compound inequality.

Solution : We have given 2d + 3 ≤ - 11 or 3d - 9 > 15.

For 2d + 3 ≤ - 11

On subtracting both sides by 3

2d ≤ - 11 - 3.

2d ≤ - 14.

On dividing both sides by 2.

d ≤ - 7.

For 3d - 9 > 15.

On adding both sides by 9.

3d > 15 + 9.

3d > 24.

On dividing both sides by 3.

d > 8.

So, A. d ≤ - 7 or d > 8.

Therefore, A. d ≤ - 7 or d > 8.

I think the answer is C