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7 January, 14:44

The kinetic energy K (in joules) of a falling apple is represented by K=v22, where v is the speed of the apple (in meters per second). How fast is the apple traveling when the kinetic energy is 32 joules? The apple is traveling at meters per second.

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  1. 7 January, 14:54
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    Answer: 1.455 m/s

    Step-by-step explanation: k = 22v defines the motion of falling apple.

    With k as kinetic energy and v as velocity.

    We are to find the value of v at k = 32 joules

    32 = 22v

    v = 32 / 22

    v = 1.455 m/s
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