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29 November, 00:26

The distance d of a particle moving in a straight line is given by d (t) = 2t^3 + 5t - 2, where t is given in seconds and d is measured in meters. Find the velocity of the particle for t = 7 seconds.

152 m/s

47 m/s

733 m/s

299 m/s

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  1. 29 November, 02:34
    0
    Answer: 299 m/s

    Step-by-step explanation:

    The first step is to take the first derivative of the equation given. This will give us the equation for velocity which we will then substitute the 7 in for t.

    To derive the equation you multiply the coefficient by the power of the variable, then subtract one from the variable.

    v (t) = 6t^2 + 5

    Now input 7 in for t to find the velocity.

    v (7) = 6 (7) ^2 + 5

    v (7) = 299 m/s
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