Ask Question
9 August, 11:15

A contractor is checking the height of the frame for a building his company is constructing. He stands at some distance from the building and measures the angle of elevation to be 73 degrees. He moves back 10 feet and measures the angle to be 68 degrees. How tall is the building?

+4
Answers (1)
  1. 9 August, 11:47
    0
    about 102 feet

    Step-by-step explanation:

    From the definition of the cotangent function, we can write ...

    h·cot (α1) = d1

    h·cot (α2) = d2

    Where h is the building height and (α1, d1), (α2, d2) are (elevation angle, distance from the building) for the two cases.

    We have d2 - d1 = 10 ft, so ...

    h (cot (68°) - cot (73°)) = 10 ft

    h = (10 ft) / (cot (68°) - cot (73°)) ≈ (10 ft) / (0.404026 - 0.305731) ≈ 101.73 ft

    The building is about 102 feet tall.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A contractor is checking the height of the frame for a building his company is constructing. He stands at some distance from the building ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers