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22 March, 06:15

How many solutions for x does the following equation have? 4/5 (20x+5) = 16x-2 A. infinite B. 1 C. - 2 D. 0

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  1. 22 March, 06:32
    0
    A. infinite

    Step by step

    4/5 (20x + 5) = 16x - 2

    16x + 4 = 16x - 2

    16x - 16x = - 2 - 4

    0x = - 6

    x = - 6/0

    x = infinite
  2. 22 March, 09:38
    0
    The correct answer is A
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