1. If m< 1 = 7x + 6 and m2 2 = 8x - 6, find the value of x so that p is

perpendicular to q.

7x + 6 = 8x - 6

x = 12

Step-by-step explanation:

put them equal to each other then subtract 8x from both sides 7x (-8x) + 6 = 8x (-8x) - 6 to get - 1x - 1x + 6 = - 6 then subtract 6 from both sides - 1x + 6 (-6) = - 6 (-6) you'll get - 1x = - 12 then divide - 1 to both sides - 1x/-1 = - 12/-1 then you get x = 12