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31 October, 00:51

slope-intercept form for the line that passes through (10, 5), and is perpendicular to the graph of 5x + 4y = 8

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  1. 31 October, 02:23
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    Step-by-step explanation:

    The equation of a straight line can be represented in the slope intercept form as

    y = mx + c

    Where

    m = slope

    c = intercept

    The equation of the given line is

    5x + 4y = 8

    Rearranging the equation so that it looks like the slope intercept form, it becomes

    4y = - 5x + 8

    y = - 4/5 + 8/4

    y = - 4/5 / + 2

    Slope, m = - 4/5

    For two lines to be perpendicular, it means that the slope of one line is equal to the negative reciprocal of the slope of the other line. It means that the slope of the line perpendicular to the given line is 5/4.

    The line passes through (10, 5). We would determine the intercept by substituting m = 5/4, x = 10 and y = 5 into y = mx + c. It becomes

    5 = 5/4 * 10 + c

    5 = 25/2 + c

    c = 5 - 25/2 = - 15/2

    The equation becomes

    y = 5x/4 - 15/2
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