Ask Question
27 July, 16:13

The position of the particle moving in space at time t ≥ 0 is r (t) = (2 + 2 cos (t)) i - 2 sin (t) j + (3 - t π) k. Find the first time moment t0 such that the velocity vector v (t0) is orthogonal to the vector i - j.

+2
Answers (1)
  1. 27 July, 18:13
    0
    t0 = π/4

    Step-by-step explanation:

    The velocity v (t) = r' (t) =

    Since ⊥v, •v=0. So,

    (1) (-2sint) + (-1) (-2cost) = 0

    cost - sint = 0
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The position of the particle moving in space at time t ≥ 0 is r (t) = (2 + 2 cos (t)) i - 2 sin (t) j + (3 - t π) k. Find the first time ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers