Use d=1/2gt2 and solve for the time one spends moving upward in a 0.6-m vertical jump. Then double it for the "hang time"-the time one's feet are off the ground. Express your answer to two significant figures and include the appropriate units.

t = 0.35 seconds

Step-by-step explanation:

We have given the equation:

d=1/2gt²

where,

g = 9.8 m/s²

d = 0.6 m

t = ?

Now put the values in the given formula:

d*2/g = t²

0.6*2/9.8 = t²

1.2/9.8 = t²

0.12245 = t²

Now find the square root of both sides

√t² = √0.12245

t = 0.35 seconds