A commuter railway has 800 passengers a day and charges each one 2 dollars.?

For each 10 cents the fair is increased, 2 fewer people will ride the train. Express the income I from the train in terms of the ticket price p (in dollars). T/F

I = - 20p^2 + 840p

Step-by-step explanation:

When the ticket price is $2 there are 800 passengers daily, but every $0.1 increase in ticket price the number of passengers will be decreased by 2.

You can put information into these equations of:

passenger - = (800-2x)

ticket price = p = $2 + 0.1x

Income is calculated by multiplying the number of the passenger with the ticket price. The answer will be expressed in terms of the ticket price, so we need to remove x from the passenger equation.

p = $2 + 0.1x

p-$2 = 0.1x

x = 10p - $20

If p = ticket price, the function for the number of passengers it will be:

passenger = (800-2x)

passenger = 800 - 2 (10p - $20)

passenger = 800 - 20p+40

passenger = 840 - 20p

The function of I will be:

I = passenger x ticket price

I = 840 - 20p * p

I = - 20p^2 + 840p