What are the intercepts of the function?

The x-intercepts are

Consider the function f (x) = x2 + 12x + 11.

x-intercepts:

0=x2 + 12x + 11

0 = (x + 1) (x + 11)

The y-intercept is

y-intercept

f (0) = (0) 2 + 12 (0) + 11

Step-by-step explanation:

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-1 and - 11 are x-intercepts, y-intercept = 11.

Step-by-step explanation:

given function: f (x) = x^2 + 12x + 11.

x-intercepts: value of the function when f (x) is zero.

so, 0 = x^2 + 12x + 11.

write 12x as 11x+x,

x^2 + x+11x + 11=0

common terms,

0 = (x + 1) (x + 11)

so, - 1 and - 11 are x-intercepts. because, when we substitute these as x values, the f (x) will be zero. y-intercept: value of the function f (x) when x=0 i. e, f (0).

so, y-intercept = 0+0+11 = 11.