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19 July, 07:20

Is there a solution to 2x^2+7x-4=0?

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Answers (2)
  1. 19 July, 10:56
    0
    Ax^2+bx+c=0

    always answer is:

    -b + (b^2-4ac) / 2a

    and

    -b - (b^2-4ac) / 2a
  2. 19 July, 11:00
    0
    x = - 8 x = 1
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