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11 March, 01:47

How do you solve

f (x) = -2 (x+3) ^2 = 5

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Answers (1)
  1. 11 March, 02:58
    0
    x = (-6+/-sqrt (10) * i) / 2

    Step-by-step explanation:

    -2 (x+3) ^2=5

    -2 (x+3) (x+3) = 5

    -2 (x^2+3x+3x+9) = 5

    -2 (x^2+6x+9) = 5

    -2x^2-12x-18=5

    -2x^2-12x-18-5=0

    -2x^2-12x-23=0

    2x^2+12x+23=0

    Apply the quadratic formula,

    you get x = (-6+/-sqrt (10) * i) / 2.
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