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17 July, 08:11

Is the following function an even function, an odd function, or neither? y=6x^2+5x

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  1. 17 July, 08:24
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    Neither

    Step-by-step explanation:

    f (x) = 6x^2 + 5x.

    If a function is even them f (x) = f (-x), so here we have:

    f (-x) = 6 (-x) ^2 + 5 (-x)

    = 6x^2 - 5x so it is not even.

    If it is odd then - f (x) = f (-x) so:

    - f (x) = - 6x^2 - 5x which is not equal to f (-x) so it is neither.
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