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8 August, 17:11

Let f and g be differentiable functions such that f (1) = 2, f' (1) = 3, f' (2) = - 4, g (1) = 2, g' (1) = - 3, g' (2) = 5. If h (x) = f (g (x)), then h' (1) =

+4
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  1. 8 August, 20:24
    0
    12

    Step-by-step explanation:

    h (x) = f (g (x))

    Using chain rule:

    h' (x) = f' (g (x)) g' (x)

    h' (1) = f' (g (1)) g' (1)

    h' (1) = f' (2) g' (1)

    h' (1) = - 4 * - 3

    h' (1) = 12
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