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2 April, 19:46

Use substitution to solve s+a=4 and 35+5a=2550

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Answers (2)
  1. 2 April, 20:50
    0
    S + a = 4

    35 + 5a = 2550

    From the second equation:

    35 + 5a = 2550

    5a = 2550 - 35

    5a = 2515

    a = 2515/5

    a = 503

    From s + a = 4

    s + 503 = 4

    s = 4 - 503

    s = - 499

    Therefore a = 503, s = - 499
  2. 2 April, 23:26
    0
    35+5 (4-s) = 2550

    35+20-5s=2550

    55-5s=2550

    -55 - 55

    -5s = 2495

    s = - 499

    -499 + a = 4

    +499 + 499

    a = 503
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