Find the length of the hypotenuse of a triangle if one of its legs is 11 cm long and its perimeter is 132 cm.

1.)

132 cm - 11 cm = 121 cm

So let the hypotenuse be x and the other leg be (121 - x).

11^2 + (121 - x) ^2 = x^2

121 + 121^2 - 121 (2) x = 0

x = 1/2 + 121/2 = 61 cm

Step-by-step explanation: not sure if this is right or not