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5 September, 21:32

When the natural number n was increased by 1, its square increased by 1001. Find n

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  1. 5 September, 21:47
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    Let n^2 = x

    Thus,

    (n + 1) ^2 = (x + 1001)

    (n + 1) ^2 - 1001 = x

    substitute x with n^2, getting:

    (n + 1) ^2 - 1001 = n^2

    (n^2 + 2n + 1) - 1001 = n^2

    n^2 - n^2 + 2n = 1001 - 1

    2n = 1000

    n = 500
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