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7 November, 23:15

What is the equation of a line parallel to y=-2x+10 that contains (6,8)

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  1. 8 November, 02:03
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    y=-2x+20

    Step-by-step explanation:

    Line is parallel to y=-2x+10, then slope that line is - 2=k.

    A (6,8) ... x1=6, y1 = 8

    y-y1=k (x-x1)

    y-8=-2 (x-6)

    y-8=-2x+12

    y=-2x+12+8

    y=-2x+20
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