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30 May, 08:42

Consider a biased coin with the probability of turning up head 0 < p < 1. We flip the coin 10 times and get a sequence of outcomes: {T, H, H, T, T, H, H, H, T, H}. We know that the probability (likelihood) of observing this sequence.

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  1. 30 May, 10:38
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    Probability of obtaining 6H and 4T = 0.2051

    Step-by-step explanation:

    Since for a fair coin,

    Probability of obtaining Head = 0.5

    p = 0.5

    q = 1-p = 0.5

    Probability of obtaining 6H and 4T = 10C6 (p) ^6 (q) ^4 = 210*0.5^6*0.5^4

    P (6H, 4T) = 0.2051
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