Ask Question
26 September, 11:59

If f (1) = 4f (1) = 4 and f (n) = f (n-1) ^2+4f (n) = f (n-1) + 4 then find the value of f (3) f (3).

+5
Answers (1)
  1. 26 September, 12:51
    0
    404

    Step-by-step explanation:

    Use the recursive formula until you get to the term you want.

    f (1) = 4

    f (2) = f (1) ^2 + 4 = 4^2 + 4 = 20

    f (3) = f (2) ^2 + 4 = 20^2 + 4 = 404
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If f (1) = 4f (1) = 4 and f (n) = f (n-1) ^2+4f (n) = f (n-1) + 4 then find the value of f (3) f (3). ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers