Find the equation of the axis of symmetry of the following parabola algebraically.

y=2x^2-4x-14

y=2x

2

-4x-14

x = 1

Step-by-step explanation:

y = 2x² - 4x - 14

y = 2 (x² - 2x) - 14

y = 2 (x² - 2x + 1) - 14 - 2 (1)

y = 2 (x - 1) ² - 16

The vertex of the parabola is at (1, - 16). So the equation of the line of symmetry is x = 1.