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14 April, 04:25

1) 3 х + 8 y = 30

бx + 7y = 6

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  1. 14 April, 06:26
    0
    Multiply the first equation my 2 and than subtract the two equations to eliminate x

    6x+16y=60-

    6x+7y=6

    9y=54

    Y=6

    Then plug in y to one of the equations

    6x+7 (6) = 6

    6x+42=6

    6x=-36

    X=-6

    X=-6 Y=6
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