Ask Question
6 March, 11:41

What are the zeros of y=4x^2+3x-1?

+2
Answers (1)
  1. 6 March, 14:56
    0
    Answer: The zeros are x = 1 / 4 or

    x = - 1

    Step-by-step explanation:

    The given equation is expressed as

    y = 4x² + 3x - 1

    To determine the zeros of the quadratic equation, we would equate it to zero first. It becomes

    4x² + 3x - 1 = 0

    We would apply the method of factorization. We would find two numbers such that their sum or difference is 3x and their product is - 4x². The two numbers are 4x and

    - x. Therefore,

    4x² + 4x - x - 1 = 0

    4x (x + 1) - 1 (x + 1) = 0

    4x - 1 = 0 or x + 1 = 0

    x = 1 / 4 or x = - 1
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What are the zeros of y=4x^2+3x-1? ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers