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22 October, 22:54

One number is seven more than twice another. If their sum is decreased my ten the result is twelve. Find the numbers

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  1. 23 October, 02:16
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    5, 17

    Step-by-step explanation:

    For this problem, you need to create a system of equations.

    We can name one number x and the other y.

    First equation: 2x + 7 = y

    Second equation: x + y - 10 = 12, or x + y = 22.

    We know y = 2x + 7, so we can substitute that into the second equation.

    x + 2x + 7 = 22.

    3x = 15

    x = 5.

    Plug x back into the first equation:

    2 · 5 + 7 = y.

    y = 10 + 7

    y = 17.
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