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27 June, 05:18

use the intermediate value theorem to determine, if possible, whether g (x) = 2x^3+3x^2-3x+4 has a real zero between - 2 and - 1

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  1. 27 June, 05:54
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    Step-by-step explanation:

    g (-2) = 2 (-2) ^3+3 (-2) ^2-3 (-2) + 4=-16+12+6+4=6

    g (-1) = 2 (-1) ^3+3 (-1) ^2-3 (-1) + 4=-2+3+3+4=8

    it does not change sign, so there is no real zero between - 2 and - 1.
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