Ask Question
17 January, 06:39

Ty's experimental probability of winning a certain game is 1/3. Jana's expiremental probability of winning the same game is 3/4. If Ty and Jana each played the game 120 times, how many more games would Jana expect to win over Ty?

+5
Answers (1)
  1. 17 January, 09:42
    0
    Jana is expected to win 40 more games over Ty.

    Step-by-step explanation:

    If Ty plays the game 120 times, he is expected to win in 1/3 part of 120 games, which is (1/3 * 120 = ) 40 games.

    If Jana plays the game 120 times, she is expected to win in 2/3 part of 120 games, which is (2/3 * 120 = ) 80 games.

    If Jana is expected to win 80 times an Ty is expected to 40 times, then Jana is expected to win (80 - 40 = ) 40 more games over Ty.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Ty's experimental probability of winning a certain game is 1/3. Jana's expiremental probability of winning the same game is 3/4. If Ty and ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers