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12 October, 22:12

Hallar el área y el perímetro de un rombo cuyas diagonales menor y mayor miden, respectivamente, 10 cm y 24 cm

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  1. 12 October, 22:21
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    The area is 120 cm²

    the perimeter is 52 cm

    Step-by-step explanation:

    The rhombus area is given by:

    A = D * d / 2

    that is, the larger diagonal D by the smaller diagonal d, between two, we know that D = 24 cm and d = 10 cm, replacing:

    A = 24 * 10/2

    A = 120

    The area is 120 cm²

    To calculate the perimeter use the Pythagorean theorem

    h² = a² + b²

    Since if you look at the rhombus it is formed by four right triangle we will take 1 of them with the following measures 5 cm (10/2) and height 12 cm (24/2) and replace:

    h² = 5² + 12²

    h² = 169

    h = 13

    now, the perimeter would be the sum of all its sides, which in this case are equal and measure 13 cm, therefore:

    p = 4 * 13

    p = 52

    which means that the perimeter is 52 cm
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