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16 January, 21:28

A baseball player hit 60 home runs in a season. Of the 60 home runs, 19 went to right field, 18 went to right center field, 12 went to center field, 10 went to left center field, and 1 went left field.

1) What is the probability that a randomly selected home run was hit to the right field?

2) What is the probability that a randomly selected home run was hit to left field?

3) Was it unusual for this player to hit a home run to left field? Explain.

A. No, because Upper P left parenthesis right-center field right parenthesis greater than 0.05. No because P (right center field) >0.05.

B. Yes, because of P (right center-right center field) less than<0.5.

C. No, because the probability of an unusual event is 0.

D. No, because this player hit 19 home runs to right center field.

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Answers (1)
  1. 17 January, 00:17
    0
    1. 19/60 = 0.32

    2. 1/60 = 0.12

    Step-by-step explanation:

    Right field = 19

    Right center field = 18

    Center field = 12

    Left center field = 10

    Left field = 1

    Total home runs = 60

    Let P stand for Probability

    Then

    1. P (right field) = 19/60 = 0.32

    2. P (left field) = 1/60 = 0.12

    3. Option C is the answer because the probability of an unusual events is less than 0.05. so 0 is also less than 0.05
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