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23 September, 02:48

G 1) a2 + 3a - 40 = 0.

solving quadratic equations

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Answers (1)
  1. 23 September, 05:26
    0
    The solution set is {-8, 5}.

    Step-by-step explanation:

    a^2 + 3a - 40 = 0.

    We need 2 numbers whose product is - 40 and whose sum is + 3.

    They would be + 8 and - 5, so we have the factors:

    (a + 8) (a - 5) = 0

    Now either a + 8 = 0 or a - 5 = 0, so:

    a = - 8 or 5.
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