An astronaut drops a rock into a crater on the moon. The distance, d (t), in meters, the rock travels after t seconds can be modeled by the function d (t) = 0.8t². What is the average speed, in meters per second, of the rock between 5 and 10 seconds after it was dropped?

13.5m/s

Step-by-step explanation:

We are asked to calculate the average speed between 5 and 10 seconds of the rock.

Generally, average speed is calculated by the total distance divided by the total time

let's start with time t = 5 seconds

The distance traveled here is: 0.8 (5) ^2 = 12.5m

For the ten seconds, t = 10 seconds

The distance traveled here is: 0.8 (10) ^2 = 80m

The average speed would thus be (80 - 12.5) / (10 - 5) = 67.5/5 = 13.5m/s