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14 July, 06:00

Solve the following equation by making an appropriate substitution. x Superscript negative 2 Baseline minus 2 x Superscript negative 1 Baseline minus 15 equals 0 Make an appropriate substitution and rewrite the equation in quadratic form. Let uequals xz-1 x Superscript negative 1 , then the quadratic equation in u is u^2-2u-15 (-5) (u+3) (u-5) (u+3).

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  1. 14 July, 06:19
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    u^2-2u-15 = 0

    Step-by-step explanation:

    If you make the substitution ...

    u equals x Superscript negative 1 Baseline

    then you can rewrite the equation as shown above.
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