Two cars leave towns 600 kilometers apart at the same time and travel toard each other. One car's rate is 18 kilometers per hour more than the other's. If they meet in 3 hours, what is the rate of the slowest carw?

Rate = 91 km/hr

Step-by-step explanation:

In this question, Rate = Speed

Speed (s) = Distance (d) / time (t)

Distance = 600 km

Time = 3 hrs for both cars

Speed for car A = x

Speed for car B = (18+x)

Distance traveled for car A = x * 3

Distance traveled for car B = (18+x) * 3

Remember that the total distance traveled = 600 km

3x + 3 * (18+x) = 600

3x + 54 + 3x = 600

6x = 600 - 54 = 546

x = 546/6 = 91

Speed of the slower car is 91 km/hr.