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17 May, 04:00

12vx^2y^8-28v^4x^9

What is the answer

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Answers (2)
  1. 17 May, 05:50
    0
    48vx^x (16y^2-21v) a lot of steps but you got this
  2. 17 May, 07:41
    0
    6vx2 • (3v4x6 - 2y6)

    Step-by-step explanation:

    18v5x8-12vx2y6

    Final result:

    6vx2 • (3v4x6 - 2y6)

    Step by step solution:

    Step 1:

    Equation at the end of step 1:

    ((18• (v5)) • (x8)) - ((22•3vx2) •y6)

    Step 2:

    Equation at the end of step 2:

    ((2•32v5) • x8) - (22•3vx2y6)

    Step 3:

    Step 4:

    Pulling out like terms:

    4.1 Pull out like factors:

    18v5x8 - 12vx2y6 = 6vx2 • (3v4x6 - 2y6)

    Trying to factor as a Difference of Squares:

    4.2 Factoring: 3v4x6 - 2y6

    Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

    Proof : (A+B) • (A-B) =

    A2 - AB + BA - B2 =

    A2 - AB + AB - B2 =

    A2 - B2

    Note : AB = BA is the commutative property of multiplication.

    Note : - AB + AB equals zero and is therefore eliminated from the expression.

    Check : 3 is not a square!

    Ruling : Binomial can not be factored as the

    difference of two perfect squares

    Trying to factor as a Difference of Cubes:

    4.3 Factoring: 3v4x6 - 2y6

    Theory : A difference of two perfect cubes, a3 - b3 can be factored into

    (a-b) • (a2 + ab + b2)

    Proof : (a-b) • (a2+ab+b2) =

    a3+a2b+ab2-ba2-b2a-b3 =

    a3 + (a2b-ba2) + (ab2-b2a) - b3 =

    a3+0+0+b3 =

    a3+b3

    Check : 3 is not a cube!

    Ruling : Binomial can not be factored as the difference of two perfect cubes

    Final result:

    6vx2 • (3v4x6 - 2y6) 18v5x8-12vx2y6

    Final result:

    6vx2 • (3v4x6 - 2y6)

    Step by step solution:

    Step 1:

    Equation at the end of step 1:

    ((18• (v5)) • (x8)) - ((22•3vx2) •y6)

    Step 2:

    Equation at the end of step 2:

    ((2•32v5) • x8) - (22•3vx2y6)

    Step 3:

    Step 4:

    Pulling out like terms:

    4.1 Pull out like factors:

    18v5x8 - 12vx2y6 = 6vx2 • (3v4x6 - 2y6)

    Trying to factor as a Difference of Squares:

    4.2 Factoring: 3v4x6 - 2y6

    Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

    Proof : (A+B) • (A-B) =

    A2 - AB + BA - B2 =

    A2 - AB + AB - B2 =

    A2 - B2

    Note : AB = BA is the commutative property of multiplication.

    Note : - AB + AB equals zero and is therefore eliminated from the expression.

    Check : 3 is not a square!

    Ruling : Binomial can not be factored as the

    difference of two perfect squares

    Trying to factor as a Difference of Cubes:

    4.3 Factoring: 3v4x6 - 2y6

    Theory : A difference of two perfect cubes, a3 - b3 can be factored into

    (a-b) • (a2 + ab + b2)

    Proof : (a-b) • (a2+ab+b2) =

    a3+a2b+ab2-ba2-b2a-b3 =

    a3 + (a2b-ba2) + (ab2-b2a) - b3 =

    a3+0+0+b3 =

    a3+b3

    Check : 3 is not a cube!

    Ruling : Binomial can not be factored as the difference of two perfect cubes

    Final result:

    6vx2 • (3v4x6 - 2y6)
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