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Mathematics
Bridger
17 May, 04:00
12vx^2y^8-28v^4x^9
What is the answer
+4
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2
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Melany Howell
17 May, 05:50
0
48vx^x (16y^2-21v) a lot of steps but you got this
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Israel Hendrix
17 May, 07:41
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6vx2 • (3v4x6 - 2y6)
Step-by-step explanation:
18v5x8-12vx2y6
Final result:
6vx2 • (3v4x6 - 2y6)
Step by step solution:
Step 1:
Equation at the end of step 1:
((18• (v5)) • (x8)) - ((22•3vx2) •y6)
Step 2:
Equation at the end of step 2:
((2•32v5) • x8) - (22•3vx2y6)
Step 3:
Step 4:
Pulling out like terms:
4.1 Pull out like factors:
18v5x8 - 12vx2y6 = 6vx2 • (3v4x6 - 2y6)
Trying to factor as a Difference of Squares:
4.2 Factoring: 3v4x6 - 2y6
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 3 is not a square!
Ruling : Binomial can not be factored as the
difference of two perfect squares
Trying to factor as a Difference of Cubes:
4.3 Factoring: 3v4x6 - 2y6
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 + ab + b2)
Proof : (a-b) • (a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3 + (a2b-ba2) + (ab2-b2a) - b3 =
a3+0+0+b3 =
a3+b3
Check : 3 is not a cube!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Final result:
6vx2 • (3v4x6 - 2y6) 18v5x8-12vx2y6
Final result:
6vx2 • (3v4x6 - 2y6)
Step by step solution:
Step 1:
Equation at the end of step 1:
((18• (v5)) • (x8)) - ((22•3vx2) •y6)
Step 2:
Equation at the end of step 2:
((2•32v5) • x8) - (22•3vx2y6)
Step 3:
Step 4:
Pulling out like terms:
4.1 Pull out like factors:
18v5x8 - 12vx2y6 = 6vx2 • (3v4x6 - 2y6)
Trying to factor as a Difference of Squares:
4.2 Factoring: 3v4x6 - 2y6
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 3 is not a square!
Ruling : Binomial can not be factored as the
difference of two perfect squares
Trying to factor as a Difference of Cubes:
4.3 Factoring: 3v4x6 - 2y6
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 + ab + b2)
Proof : (a-b) • (a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3 + (a2b-ba2) + (ab2-b2a) - b3 =
a3+0+0+b3 =
a3+b3
Check : 3 is not a cube!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Final result:
6vx2 • (3v4x6 - 2y6)
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