If m = 6n + 1 and m = 4n + 19, what is the m

A 10n + 20

B 55

C 7n

D 110

To solve:

If m = 6n+1 and m = 4n + 19 and m=m then you use substitution and can solve by setting 6n+1=4n+19

6n+1=4n+19 - - add like terms (6n-4n=2n)

2n+1=19--get n by itself subtract 1 on each side

2n=18

n=9

If you plug n as 9 back into the equation,

6 (9) + 1=55

4 (9) + 19=55

Therefore m=55