Rewrite (x + 3) ^2 - 3 (x + 3) - 10 as the product of two binomials

Step-by-step explanation:

(x + 3) ^2 - 3 (x + 3) - 10 = (x + 3) (x + 3) - 3 (x + 3) - 10

= (x + 3) [ (x + 3) - 3 ] - 10

= (x + 3) [ x + 3 - 3 ] - 10

= (x + 3) * x - 10 = x² + 3x - 10

= x² - 2x + 5x - 10

= x (x - 2) + 5 (x - 2)

= (x-2) (x+5)

(X+2) and (X-5)

Step-by-step explanation: (X+3) * x-3 (X+3) - 10

= (X*2+6X+9) - (3X+9) - 10

=X*2+6X+9-3X-9-10

=X*2+3X-10

X = (-b+ / - (b*2-4ac) * 1/2) / 2a

a=1, b=3, c=-10

=-3+ / - ((3) * x-4 (1) 9-10)) * 1/2/2 (1)

=-3+ / - (9+40) / 2

= (-3+/-7) 2

Therefore 1. (-3-7) / 2, and 2. ((-3+7)) / 2

1. - 10/2=-5, X=-5 therefore (X+5)

2. (4/2) = 2, X=2 therefore (X-2)